Check if given String is Palindrome in Python

Write a program that reads a string from the user and uses a loop to determines whether or not it is a palindrome. Display the result, including a meaningful output message. [A string is a palindrome if it is identical forward and backward.]

import re
 
 
Continue = 1
Quit = 2
 
 
def main():
    choice = 0
 
    while choice != Quit:
        # Display the menu.
        display_menu()
        # Constant to assume string is Palindrome
        is_palindrome = True
 
        # Get the user's choice.
        choice = int(input('\nEnter your choice: '))
 
        # Perform the selected action.
        if choice == Continue:
            line = input("\nEnter a string: ")
            str_lower = re.sub("[^a-z0-9]", "", line.lower())
            for i in range(0, len(str_lower)//2):
                if str_lower[i] != str_lower[len(str_lower) - i - 1]:
                    is_palindrome = False
 
            if is_palindrome:
                print(line, "is a palindrome")
            else:
                print(line, "is not a palindrome")
        else:
            print('Thank You.')
 
 
def display_menu():
    print('\n*******MENU*******')
    print('1) Continue')
    print('2) Quit')
 
 
main()

Sample output of above program.

*******MENU*******

1) Continue

2) Quit

 

Enter your choice: 1

 

Enter a string: A dog! A panic in a pagoda!

A dog! A panic in a pagoda! is a palindrome

 

*******MENU*******

1) Continue

2) Quit

 

Enter your choice: 1

 

Enter a string: Civic

Civic is a palindrome

 

*******MENU*******

1) Continue

2) Quit

 

Enter your choice: 1

 

Enter a string: Python vs Java

Python vs Java is not a palindrome

 

*******MENU*******

1) Continue

2) Quit

 

Enter your choice: 2

Thank You.